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The stability of Me2C = CH2 is more than that of MeCH2CH = CH2 due to A. inductive effect of the Me group B. resonance effect of the Me group C. hyperconjugative effect of the Me group D. resonance as well as inductive effect of the Me group

The stability of Me2C = CH2
is more than that of MeCH2CH = CH2
due to
A. inductive effect of the Me group
B. resonance effect of the Me group
C. hyperconjugative effect of the Me group
D. resonance as well as inductive effect of the Me group

Grade:

2 Answers

Arun
25750 Points
3 years ago
In Me2​C=CH2​, with respect to Alkene the number of 
α-Hydrogen atoms are 6 (i.e. the number of hydrogen atoms taking part in hyperconjugation).
While in MeCH2​CH=CH2​, the number of α-Hydrogen atoms are 2.
So, the extent of hyperconjugation is more in Me2​C=CH2​ than in MeCH2​CH=CH2​.
Thus, Me2​C=CH2​ is more stable than MeCH2​CH=CH2​.
So, the correct answer is option C.
Vikas TU
14149 Points
3 years ago
(Me)2C=CH2 has 6 hyper conjugate forms while (MeCH2)(HC)=CH2 has 2 hyper conjugate forms .Therefore Me2C=CH2 is more  stable than MeCH2CH=CH2 

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