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The solution was prepared by dissolving 0.0005 mol of Ba (OH)2 in 100 ml of the solution. If the base is assume to ionize completely, the pOH of the solution will be A. 10 B. 12 C. 2 D. unpredictable

The solution was prepared by dissolving 0.0005 mol of Ba (OH)2 in 100 ml of the solution. If the base is assume to ionize completely, the pOH of the solution will be
A. 10 B. 12 C. 2 D. unpredictable

Grade:Upto college level

2 Answers

Saurabh Koranglekar
askIITians Faculty 10341 Points
11 months ago
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Vikas TU
14149 Points
11 months ago
Ba (OH)2 is completely dissociated and so
Ba(OH)2---> Ba++ + 2OH-
so 0.005M yields 0.005*2=0.01 moles of OH-
So, pOH =log 1/[OH-] = log 1/10^-2= log 10^2 = 2
pH+pOH= 14
Answer= pH=14-2=12

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