The sides (in meters) of a box joining at origin are represented by vectors
a= 4i, b= 2i + 3j and c= i+k. The surface area of the box is
a) 20 m2 b) 26 m2 c) 36 m2
d) 40 m
2

Question

The sides (in meters) of a box joining at origin are represented by vectors a= 4i, b= 2i + 3j and c= i+k. The surface area of the box is a) 20 m2 b) 26 m2 c) 36 m2 d) 40 m 2

Saurabh Koranglekar · Answer

Dear student Please find the link below https://www.askiitians.com/forums/General-Physics/the-sides-in-meters-of-a-box-joining-at-origin-a_143982.htm Regards

Vikas TU · Answer

Surface area for cuboid is: 2*(l.b + b.h + h.l) => here . is dot product. therfore, => 2*(8 + 2 + 4) =>2*(14) => 28 m^2

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The sides (in meters) of a box joining at origin are represented by vectors a= 4i, b= 2i + 3j and c= i+k. The surface area of the box is a) 20 m2 b) 26 m2 c) 36 m2 d) 40 m 2

The sides (in meters) of a box joining at origin are represented by vectors
a= 4i, b= 2i + 3j and c= i+k. The surface area of the box is
a) 20 m2 b) 26 m2 c) 36 m2
d) 40 m
2

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The sides (in meters) of a box joining at origin are represented by vectors a= 4i, b= 2i + 3j and c= i+k. The surface area of the box is a) 20 m2 b) 26 m2 c) 36 m2 d) 40 m 2

The sides (in meters) of a box joining at origin are represented by vectors a= 4i, b= 2i + 3j and c= i+k. The surface area of the box is a) 20 m2 b) 26 m2 c) 36 m2 d) 40 m 2

2 Answers

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The sides (in meters) of a box joining at origin are represented by vectors
a= 4i, b= 2i + 3j and c= i+k. The surface area of the box is
a) 20 m2 b) 26 m2 c) 36 m2
d) 40 m
2