The set of values of m for which both the roots of the equation x2 - (m + 1)x + m + 4 = 0 are real and negative consists of all m, such that
A. -3 = m or m = 5 B. -3 < m = 5 C. - 4 < m = -3 D. -3 < m = -1

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Saurabh Koranglekar · Answer

Vikas TU · Answer

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The set of values of m for which both the roots of the equation x2 - (m + 1)x + m + 4 = 0 are real and negative consists of all m, such that A. -3 = m or m = 5 B. -3 < m = 5 C. - 4 < m = -3 D. -3 < m = -1

The set of values of m for which both the roots of the equation x2 - (m + 1)x + m + 4 = 0 are real and negative consists of all m, such that
A. -3 = m or m = 5 B. -3 < m = 5 C. - 4 < m = -3 D. -3 < m = -1

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The set of values of m for which both the roots of the equation x2 - (m + 1)x + m + 4 = 0 are real and negative consists of all m, such that A. -3 = m or m = 5 B. -3 < m = 5 C. - 4 < m = -3 D. -3 < m = -1

The set of values of m for which both the roots of the equation x2 - (m + 1)x + m + 4 = 0 are real and negative consists of all m, such that A. -3 = m or m = 5 B. -3 < m = 5 C. - 4 < m = -3 D. -3 < m = -1

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The set of values of m for which both the roots of the equation x2 - (m + 1)x + m + 4 = 0 are real and negative consists of all m, such that
A. -3 = m or m = 5 B. -3 < m = 5 C. - 4 < m = -3 D. -3 < m = -1