The ratio of magnetic field and magnetic moment at the centre of a current carrying circular loop is x. When both the current and
radius is doubled the ratio will be
(A) x / 8 (B) x / 4 (C) x / 2 (D) 2x
aniket anand , 11 Years ago
Grade
2 Answers
Arun
Last Activity: 5 Years ago
The ratio of magnetic field and magnetic moment at the centre of a current carrying circular loop is x. When both the current and radius is doubled the ratio will be. x/8.
Vikas TU
Last Activity: 5 Years ago
Dear student B = mew *i/2a B/M = x (given) When both current and the radius re doubled mew /(2*pi*(2a)^3) = x/8
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