Thank you for registering.

One of our academic counsellors will contact you within 1 working day.

Please check your email for login details.
MY CART (5)

Use Coupon: CART20 and get 20% off on all online Study Material

ITEM
DETAILS
MRP
DISCOUNT
FINAL PRICE
Total Price: Rs.

There are no items in this cart.
Continue Shopping

The ratio of magnetic field and magnetic moment at the centre of a current carrying circular loop is x. When both the current and radius is doubled the ratio will be (A) x / 8 (B) x / 4 (C) x / 2 (D) 2x

The ratio of magnetic field and magnetic moment at the centre of a current carrying circular loop is x. When both the current and
radius is doubled the ratio will be
(A) x / 8 (B) x / 4 (C) x / 2 (D) 2x

Grade:

2 Answers

Arun
25763 Points
one year ago
The ratio of magnetic field and magnetic moment at the centre of a current carrying circular loop is x. When both the current and radius is doubled the ratio will be. x/8.
Vikas TU
14149 Points
one year ago
Dear student 
B = mew *i/2a
B/M = x (given)
When both current and the radius re doubled 
mew /(2*pi*(2a)^3) = x/8 

Think You Can Provide A Better Answer ?

Provide a better Answer & Earn Cool Goodies See our forum point policy

ASK QUESTION

Get your questions answered by the expert for free