The ratio of magnetic field and magnetic moment at the centre of a current carrying circular loop is x. When both the current and
radius is doubled the ratio will be
(A) x / 8 (B) x / 4 (C) x / 2 (D) 2x

Question

Arun · Answer

The ratio of magnetic field and magnetic moment at the centre of a current carrying circular loop is x . When both the current and radius is doubled the ratio will be. x /8.

Vikas TU · Answer

Dear student B = mew *i/2a B/M = x (given) When both current and the radius re doubled mew /(2*pi*(2a)^3) = x/8

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The ratio of magnetic field and magnetic moment at the centre of a current carrying circular loop is x. When both the current and radius is doubled the ratio will be (A) x / 8 (B) x / 4 (C) x / 2 (D) 2x

The ratio of magnetic field and magnetic moment at the centre of a current carrying circular loop is x. When both the current and
radius is doubled the ratio will be
(A) x / 8 (B) x / 4 (C) x / 2 (D) 2x

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