Engineering Entrance ExamsThe radius of the light circle observed by a fish at a depth of 12 meter is (refractive index of water = 4/3) (A) 736 (B) 7 36 (C) 536 (D) 54 aniket anand 12 Years agoGrade
Arun6 Years agosinic=μ1=r2+h2rUsing h=12 cm, μ=4/3We get r=736 cm. Hope it helpsIn case of any difficulty, please feel free to contact again Thanks and regardsArun
Vikas TU6 Years agosinθ = 1/μ = 3/4 or tanθc=3/ √(16−9) = 3/√7= R/15 impliesR=(36)/(sqrt7)`cm................................