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The radius of the light circle observed by a fish at a depth of 12 meter is (refractive index of water = 4/3)(A) 736 (B) 736(C) 536 (D) 54

aniket anand , 11 Years ago
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anser 2 Answers
Arun

Last Activity: 4 Years ago

sinic=μ1=r2+h2r
Using h=12 cm, μ=4/3
We get r=736 cm.
 
Hope it helps
In case of any difficulty, please feel free to contact again
 
Thanks and regards
Arun

Vikas TU

Last Activity: 4 Years ago

sinθ = 1/μ = 3/4 
or tanθc=3/ √(16−9) = 3/√7
= R/15 
impliesR=(36)/(sqrt7)`cm................................

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