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Engineering Entrance Exams

The radius of the light circle observed by a fish at a depth of 12 meter is (refractive index of water = 4/3) (A) 736 (B) 7 36 (C) 536 (D) 54

Profile image of aniket anand
12 Years agoGrade
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2 Answers

Profile image of Arun
6 Years ago
sinic=μ1=r2+h2r
Using h=12 cm, μ=4/3
We get r=736 cm.
 
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Arun
Profile image of Vikas TU
6 Years ago
sinθ = 1/μ = 3/4 
or tanθc=3/ √(16−9) = 3/√7
= R/15 
impliesR=(36)/(sqrt7)`cm................................

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