The probability that at least one of A and B occurs is 0.6 . If A and B occur simultaneously with probability 0.3, then P(A ) P(B ) ' ' +is(A) 0.9 (B) 0.15 (C) 1.1 (D) 1.2
aniket anand , 11 Years ago
Grade
2 Answers
Arun
Last Activity: 4 Years ago
P (AUB)=0.6,P (A intersection B)=0.2 P (AUB)=P (A)+P (B)-P (A intersection B) 0.6=P (A)+P (B)-0.2 0.6+0.2=P (A)+P (B) P (A)+P (B)=0.8 P (A bar )+P (Bbar)=(1-p (A))+(1-p (B)) =2-(P(A)+P (B)) =2-(0.8) =1.2
Vikas TU
Last Activity: 4 Years ago
P (AUB)=0.6,P (A intersection B)=0.2 P (AUB)=P (A)+P (B)-P (A intersection B) 0.6=P (A)+P (B)-0.2 0.6+0.2=P (A)+P (B) P (A)+P (B)=0.8 P (A bar )+P (Bbar)=(1-p (A))+(1-p (B)) =2-(P(A)+P (B)) =2-(0.8)
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