Question icon
Grade 12Engineering Entrance Exams

The potential energy of particle executing simple hormonic motion 0.2 sec after passing the mean position is 1/4 of its total energy. the period of oscillation is

Profile image of 9493488568
7 Years agoGrade 12
Answers icon

1 Answer

Profile image of Eshan
7 Years ago
Dear student,

Potential energy=\dfrac{1}{2}kx^2
Total energy=\dfrac{1}{2}kA^2
Therefore after t=0.2s, x=A/2
Usex=Asin \omega t
Time periodT=\dfrac{2\pi}{\omega}

question mark
Hello,
 
Can we learn and prepare for MHT-CET online ?
engineering entrance exams

Last Activity: 4 Years ago