The point (–4, 5) is the vertex of a square and one of its diagonals is 7x – y + 8 = 0. The equation of the other diagonal is
(A) 7x – y + 23 = 0 (B) 7y + x = 30 (C) 7y + x = 31 (D) x – 7y = 30
Ashwani sinha , 11 Years ago
Grade
1 Answers
Vikas TU
Last Activity: 5 Years ago
Equation of perpendicular line to 7x−y+8=0 7x−y+8=0 is x+7y=hx+7y=h which is passes through (−4, 5)(−4, 5)
h = 31
Provide a better Answer & Earn Cool Goodies
LIVE ONLINE CLASSES
Prepraring for the competition made easy just by live online class.
Full Live Access
Study Material
Live Doubts Solving
Daily Class Assignments
Ask a Doubt
Get your questions answered by the expert for free
Other Related Questions on engineering entrance exams