Thank you for registering.

One of our academic counsellors will contact you within 1 working day.

Please check your email for login details.
MY CART (5)

Use Coupon: CART20 and get 20% off on all online Study Material

ITEM
DETAILS
MRP
DISCOUNT
FINAL PRICE
Total Price: Rs.

There are no items in this cart.
Continue Shopping

The number of hours required for a current of 3.0 A to decompose electrically 18 g of water is A. 12 hours B. 24 hours C. 6 hours D. 18 hours

The number of hours required for a current of 3.0 A to decompose electrically 18 g of water is
A. 12 hours B. 24 hours C. 6 hours D. 18 hours

Grade:Upto college level

2 Answers

Saurabh Koranglekar
askIITians Faculty 10341 Points
one year ago
576-539_vc.PNG
Vikas TU
14149 Points
one year ago
H2O------->O2°+ 2e
Explanation:
So, 2faraday charge is required for reaction
Q=2*96500
=193000
Q=It
193000=3*t
t=64333.33 sec
t=64333.33/60*60
=17.87
~18hrs

Think You Can Provide A Better Answer ?

Provide a better Answer & Earn Cool Goodies See our forum point policy

ASK QUESTION

Get your questions answered by the expert for free