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The number of hours required for a current of 3.0 A to decompose electrically 18 g of water is A. 12 hours B. 24 hours C. 6 hours D. 18 hours

The number of hours required for a current of 3.0 A to decompose electrically 18 g of water is
A. 12 hours B. 24 hours C. 6 hours D. 18 hours

Grade:Upto college level

2 Answers

Saurabh Koranglekar
askIITians Faculty 10335 Points
3 years ago
576-539_vc.PNG
Vikas TU
14149 Points
3 years ago
H2O------->O2°+ 2e
Explanation:
So, 2faraday charge is required for reaction
Q=2*96500
=193000
Q=It
193000=3*t
t=64333.33 sec
t=64333.33/60*60
=17.87
~18hrs

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