The molarity of a solution obtained by mixing 750 mL of 0.5 (M) HCl with 250 mL of 2(M)HCl will be:
(1) 1.00 M
(2) 1. 75 M
(3) 0.975 M
(4) 0.875 M

Question

The molarity of a solution obtained by mixing 750 mL of 0.5 (M) HCl with 250 mL of 2(M)HCl will be: (1) 1.00 M (2) 1. 75 M (3) 0.975 M (4) 0.875 M

Saurabh Koranglekar · Answer

Vikas TU · Answer

Tha resultant molar it when two acids or two bases are mixed is given by M = M1V1+M2V2 / V1+V2 SO , M = 750*0.5 + 250*2 / 750+250 M = 375 + 500 / 1000 M = 875 /1000 = 0.875 M

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The molarity of a solution obtained by mixing 750 mL of 0.5 (M) HCl with 250 mL of 2(M)HCl will be: (1) 1.00 M (2) 1. 75 M (3) 0.975 M (4) 0.875 M

The molarity of a solution obtained by mixing 750 mL of 0.5 (M) HCl with 250 mL of 2(M)HCl will be:
(1) 1.00 M
(2) 1. 75 M
(3) 0.975 M
(4) 0.875 M

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The molarity of a solution obtained by mixing 750 mL of 0.5 (M) HCl with 250 mL of 2(M)HCl will be: (1) 1.00 M (2) 1. 75 M (3) 0.975 M (4) 0.875 M

The molarity of a solution obtained by mixing 750 mL of 0.5 (M) HCl with 250 mL of 2(M)HCl will be: (1) 1.00 M (2) 1. 75 M (3) 0.975 M (4) 0.875 M

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The molarity of a solution obtained by mixing 750 mL of 0.5 (M) HCl with 250 mL of 2(M)HCl will be:
(1) 1.00 M
(2) 1. 75 M
(3) 0.975 M
(4) 0.875 M