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Grade Upto college level Engineering Entrance Exams

The masses of two planets are in the ratio 1 : 2. Their radii are in the ratio 1 : 2. The acceleration due to gravity on the planets are in the ratio. (a) 1 : 2 (b) 2 : 1 (c) 3 : 5 (d) 5 : 3

Profile image of sumit kumar
12 Years agoGrade Upto college level
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2 Answers

Profile image of Saurabh Koranglekar
6 Years ago

To figure out the acceleration due to gravity on the two planets, we can use the formula for gravitational acceleration, which is given by:

Understanding Gravitational Acceleration

The formula for the acceleration due to gravity (g) on the surface of a planet is expressed as:

g = G * (M / R^2)

where:

  • G is the gravitational constant,
  • M is the mass of the planet, and
  • R is the radius of the planet.

Applying the Given Ratios

In this case, we know the following ratios:

  • The masses of the planets are in the ratio 1:2, so we can let the mass of the first planet be M and the mass of the second be 2M.
  • The radii are in the ratio 1:2, meaning we can let the radius of the first planet be R and the radius of the second be 2R.

Calculating the Acceleration Due to Gravity

Now, we can find the acceleration due to gravity on each planet:

  • For the first planet:
  • g₁ = G * (M / R²)

  • For the second planet:
  • g₂ = G * (2M / (2R)²)

    This simplifies to:

    g₂ = G * (2M / 4R²) = (G * (M / 2R²))

Finding the Ratio of Acceleration

Now, we can find the ratio of the gravitational accelerations:

g₁ : g₂ = (G * (M / R²)) : (G * (M / 2R²))

The G and M terms cancel out, leaving us with:

g₁ : g₂ = (1/R²) : (1/(2R²))

This simplifies to:

g₁ : g₂ = 2 : 1

Final Answer

The ratio of the accelerations due to gravity on the two planets is therefore 2:1. The correct answer is (b) 2:1.

Profile image of Vikas TU
6 Years ago
Acc to law of gravitation : mg1=GM1m/R1^2
g1= GM1 / R1^2
( considering that for the first planet variables are placed with 1 and for the second with 2 )
Similarly g2 = G M2/R2^2
As we know that M2 is twice of M1 and R2 is twice of R1
So g2= G2M1/(2R1)^2
g1/g2 = G M1/R1^2 X 4R1^2/G2M1
g1:g2 = 4:2 = 2:1
 

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