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The magnetic flux through a loop of resistance 10 ? is given by f = 5t2– 4t + 1 Weber. How much current is induced in the loopafter 0.2 sec ?(A) 0.4 A (B) 0.2 A (C) 0.04 A (D) 0.02 A

aniket anand , 11 Years ago
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anser 2 Answers
Arun

Last Activity: 4 Years ago

Given that,
Magnetic flux ϕ=5t2−4t+1
Time t=0.2sec
Now, the induced e. m. f in the circuit
E=−dtdϕ​
E=−dtd(5t2−4t+1)​
E=−10t+4
Now, at t=0.2 s
E=−10×0.2+4
E=2V
Hence, the induced emf in the circuit is 2 V

Vikas TU

Last Activity: 4 Years ago

Dear student 
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