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The light beams of intensities in the ratio of 9 : 1 are allowed to interfere. What will be the ratio of the intensities of maxima and minima ? (A) 3 : 1 (B) 4 : 1 (C) 25 : 9 (D) 81 : 1

The light beams of intensities in the ratio of 9 : 1 are allowed to interfere. What will be the ratio of the intensities of maxima and
minima ?
(A) 3 : 1 (B) 4 : 1 (C) 25 : 9 (D) 81 : 1

Grade:

2 Answers

Arun
25763 Points
11 months ago
Intensity of the wave is directly proportional to square of amplitude.
I ∝ a^2
I1/I2 = (a1/a2)^2
9/1 = (a1/a2)^2
a1/a2 = 3
a1 = 3a2
Ratio of maximum to minimum intensity by -
Imax / Imin = (a1+a2)^2 / (a1-a2)^2
Imax / Imin = (3a2+a2)^2 / (3a2-a2)^2
Imax / Imin = 4^2 / 2^2
Imax / Imin = 16 / 4
Imax / Imin = 4
Therefore, ratio of maximum to minimum intensity is 4:1.
Hope this helps you..
 
Vikas TU
14149 Points
11 months ago
The light beams with intensities being in the ratio 19, so the amplitudes are in the ratio 13. So, the maximum and minimum intensities are in the ratio (3−1)2(3+1)2=2242=416=14.

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