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The light beams of intensities in the ratio of 9 : 1 are allowed to interfere. What will be the ratio of the intensities of maxima andminima ?(A) 3 : 1 (B) 4 : 1 (C) 25 : 9 (D) 81 : 1

aniket anand , 11 Years ago
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Arun

Last Activity: 4 Years ago

Intensity of the wave is directly proportional to square of amplitude.
I ∝ a^2
I1/I2 = (a1/a2)^2
9/1 = (a1/a2)^2
a1/a2 = 3
a1 = 3a2
Ratio of maximum to minimum intensity by -
Imax / Imin = (a1+a2)^2 / (a1-a2)^2
Imax / Imin = (3a2+a2)^2 / (3a2-a2)^2
Imax / Imin = 4^2 / 2^2
Imax / Imin = 16 / 4
Imax / Imin = 4
Therefore, ratio of maximum to minimum intensity is 4:1.
Hope this helps you..
 

Vikas TU

Last Activity: 4 Years ago

The light beams with intensities being in the ratio 19, so the amplitudes are in the ratio 13. So, the maximum and minimum intensities are in the ratio (3−1)2(3+1)2=2242=416=14.

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