The length of second’s pendulum on the surface of earth is 1 m. the length of same pendulum on the surface of moon, where acceleration due to gravity is (1/6)th of the g on the surface of earth ?

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Saurabh Koranglekar · Answer

Vikas TU · Answer

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The length of second’s pendulum on the surface of earth is 1 m. the length of same pendulum on the surface of moon, where acceleration due to gravity is (1/6)th of the g on the surface of earth ?

The length of second’s pendulum on the surface of earth is 1 m. the length of same pendulum on the surface of moon, where acceleration due to gravity is (1/6)th of the g on the surface of earth ?

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The length of second’s pendulum on the surface of earth is 1 m. the length of same pendulum on the surface of moon, where acceleration due to gravity is (1/6)th of the g on the surface of earth ?

The length of second’s pendulum on the surface of earth is 1 m. the length of same pendulum on the surface of moon, where acceleration due to gravity is (1/6)th of the g on the surface of earth ?

2 Answers

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Other Related Questions on Engineering Entrance Exams

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