The height at which the acceleration due to gravity becomes
g/9
(where g = the acceleration due to gravity
on the surface of the earth) in terms of R, the radius of the earth, is ?

Question

The height at which the acceleration due to gravity becomes g/9 (where g = the acceleration due to gravity on the surface of the earth) in terms of R, the radius of the earth, is ?

Saurabh Koranglekar · Answer

Vikas TU · Answer

By Newton’s law of gravitation, g is inversely proportional to r2, So, g‘ / g = [R / R+h ] 2 Put g’ = g/9; h= 2R

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The height at which the acceleration due to gravity becomes g/9 (where g = the acceleration due to gravity on the surface of the earth) in terms of R, the radius of the earth, is ?

The height at which the acceleration due to gravity becomes
g/9
(where g = the acceleration due to gravity
on the surface of the earth) in terms of R, the radius of the earth, is ?

2 Answers

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The height at which the acceleration due to gravity becomes g/9 (where g = the acceleration due to gravity on the surface of the earth) in terms of R, the radius of the earth, is ?

The height at which the acceleration due to gravity becomes g/9 (where g = the acceleration due to gravity on the surface of the earth) in terms of R, the radius of the earth, is ?

2 Answers

Think You Can Provide A Better Answer ?

Other Related Questions on Engineering Entrance Exams

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The height at which the acceleration due to gravity becomes
g/9
(where g = the acceleration due to gravity
on the surface of the earth) in terms of R, the radius of the earth, is ?