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The height at which the acceleration due to gravity becomes g/9 (where g = the acceleration due to gravity on the surface of the earth) in terms of R, the radius of the earth, is ?

The height at which the acceleration due to gravity becomes
g/9
(where g = the acceleration due to gravity
on the surface of the earth) in terms of R, the radius of the earth, is ?

Grade:12

2 Answers

Saurabh Koranglekar
askIITians Faculty 10341 Points
one year ago
576-1162_v.PNG
Vikas TU
14149 Points
one year ago
By Newton’s law of gravitation, g is inversely proportional to r2,
So, g‘ / g = [R / R+h ] 2
Put g’ = g/9;  h= 2R

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