The function f(x)=2x^2-15x^2+36x+1 is increasing in the interval

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Sourabh Singh · Answer

Hii Take the differential and solve for zero equality. the values greater than the root function will be increasing the values less than the root function will be decreasing Thanks

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The function f(x)=2x^2-15x^2+36x+1 is increasing in the interval

The function f(x)=2x^2-15x^2+36x+1 is increasing in the interval

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The function f(x)=2x^2-15x^2+36x+1 is increasing in the interval

The function f(x)=2x^2-15x^2+36x+1 is increasing in the interval

1 Answers

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