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The force constant of a wire is K and that of another wire of the same material is 2K. when both the wires are stretched, then work done is (a) W2 = 0.5 W1 (b) W2 = W1 (c) W2 = 2W2 (d) W2 = 2W12

The force constant of a wire is K and that of another wire of the same material is 2K. when both the wires are stretched, then work done is
(a) W2 = 0.5 W1 (b) W2 = W1
(c) W2 = 2W2 (d) W2 = 2W12

Grade:Upto college level

2 Answers

Saurabh Koranglekar
askIITians Faculty 10335 Points
2 years ago
Dear student

The answer is w2 = 2w1

Regards
Vikas TU
14149 Points
2 years ago
Explanation:w1=1/2*kx/A*l/L*v
W2=1/2*2kx/A*l/L*v
Divide. w1/w2
Ans===w2=2w1.......................................................

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