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The first ionization potential of Na is 5.1 eV. The value of electron gain enthalpy of Na + will be:

The first ionization potential of Na is 5.1 eV. The value of electron gain enthalpy of Na + will be:

Grade:11

2 Answers

Saurabh Koranglekar
askIITians Faculty 10341 Points
one year ago
576-32_w.PNG
Vikas TU
14149 Points
one year ago
Na--------> Na⁺ + e⁻ ( first IE)  ΔH = 5.1

Noe reaction is reversed :-

Na⁺ + e⁻ ----------> Na

so ΔH = -5.1eV

Thank you

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