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The first ionization potential of Na is 5.1 eV. The value of electron gain enthalpy of Na + will be:

Jayant Kumar , 10 Years ago
Grade 11
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Saurabh Koranglekar

Last Activity: 4 Years ago

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Vikas TU

Last Activity: 4 Years ago

Na--------> Na⁺ + e⁻ ( first IE)  ΔH = 5.1

Noe reaction is reversed :-

Na⁺ + e⁻ ----------> Na

so ΔH = -5.1eV

Thank you

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