The first ionization potential of Na is 5.1 eV. The value of electron gain enthalpy of Na + will be:

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Saurabh Koranglekar · Answer

Vikas TU · Answer

Na--------> Na⁺ + e⁻ ( first IE) ΔH = 5.1 Noe reaction is reversed :- Na⁺ + e⁻ ----------> Na so ΔH = -5.1eV Thank you HOPE IT HELPS..

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The first ionization potential of Na is 5.1 eV. The value of electron gain enthalpy of Na + will be:

The first ionization potential of Na is 5.1 eV. The value of electron gain enthalpy of Na + will be:

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The first ionization potential of Na is 5.1 eV. The value of electron gain enthalpy of Na + will be:

The first ionization potential of Na is 5.1 eV. The value of electron gain enthalpy of Na + will be:

2 Answers

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