The equation of the circle passing through the point (1, 1) and the points of intersection of x2 + y2 – 6x – 8 = 0 and x2
+ y2 – 6 = 0 is
(A) x2 + y2 + 3x – 5 = 0 (B) x2 + y2 – 4x + 2 = 0 (C) x2 + y2 + 6x – 4 = 0 (D) x2 + y2 – 4y – 2 = 0

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Saurabh Koranglekar · Answer

Vikas TU · Answer

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The equation of the circle passing through the point (1, 1) and the points of intersection of x2 + y2 – 6x – 8 = 0 and x2 + y2 – 6 = 0 is (A) x2 + y2 + 3x – 5 = 0 (B) x2 + y2 – 4x + 2 = 0 (C) x2 + y2 + 6x – 4 = 0 (D) x2 + y2 – 4y – 2 = 0

The equation of the circle passing through the point (1, 1) and the points of intersection of x2 + y2 – 6x – 8 = 0 and x2
+ y2 – 6 = 0 is
(A) x2 + y2 + 3x – 5 = 0 (B) x2 + y2 – 4x + 2 = 0 (C) x2 + y2 + 6x – 4 = 0 (D) x2 + y2 – 4y – 2 = 0

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The equation of the circle passing through the point (1, 1) and the points of intersection of x2 + y2 – 6x – 8 = 0 and x2 + y2 – 6 = 0 is (A) x2 + y2 + 3x – 5 = 0 (B) x2 + y2 – 4x + 2 = 0 (C) x2 + y2 + 6x – 4 = 0 (D) x2 + y2 – 4y – 2 = 0

The equation of the circle passing through the point (1, 1) and the points of intersection of x2 + y2 – 6x – 8 = 0 and x2 + y2 – 6 = 0 is (A) x2 + y2 + 3x – 5 = 0 (B) x2 + y2 – 4x + 2 = 0 (C) x2 + y2 + 6x – 4 = 0 (D) x2 + y2 – 4y – 2 = 0

2 Answers

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The equation of the circle passing through the point (1, 1) and the points of intersection of x2 + y2 – 6x – 8 = 0 and x2
+ y2 – 6 = 0 is
(A) x2 + y2 + 3x – 5 = 0 (B) x2 + y2 – 4x + 2 = 0 (C) x2 + y2 + 6x – 4 = 0 (D) x2 + y2 – 4y – 2 = 0