The equation of displacement of particle performing SHM is X = 0.25 sin (200 t). The maximum velocity is
(a) 100 m/s (b) 200 m/s
(c) 50 m/s (d) 150 m/s

Question

The equation of displacement of particle performing SHM is X = 0.25 sin (200 t). The maximum velocity is (a) 100 m/s (b) 200 m/s (c) 50 m/s (d) 150 m/s

Vikas TU · Answer

v = dx /dt Maximum amplitude is maximum velocity v = 0.25 * 200 = 50 m/s C is correct ….................................

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The equation of displacement of particle performing SHM is X = 0.25 sin (200 t). The maximum velocity is (a) 100 m/s (b) 200 m/s (c) 50 m/s (d) 150 m/s

The equation of displacement of particle performing SHM is X = 0.25 sin (200 t). The maximum velocity is
(a) 100 m/s (b) 200 m/s
(c) 50 m/s (d) 150 m/s

1 Answers

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The equation of displacement of particle performing SHM is X = 0.25 sin (200 t). The maximum velocity is (a) 100 m/s (b) 200 m/s (c) 50 m/s (d) 150 m/s

The equation of displacement of particle performing SHM is X = 0.25 sin (200 t). The maximum velocity is (a) 100 m/s (b) 200 m/s (c) 50 m/s (d) 150 m/s

1 Answers

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The equation of displacement of particle performing SHM is X = 0.25 sin (200 t). The maximum velocity is
(a) 100 m/s (b) 200 m/s
(c) 50 m/s (d) 150 m/s