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The equation of displacement of particle performing SHM is X = 0.25 sin (200 t). The maximum velocity is (a) 100 m/s (b) 200 m/s (c) 50 m/s (d) 150 m/s

sumit kumar , 12 Years ago
Grade Upto college level
anser 1 Answers
Vikas TU
v = dx /dt 
Maximum amplitude is maximum velocity 
v = 0.25 * 200 = 50 m/s 
C is correct 
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Last Activity: 5 Years ago
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