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The distance between an object and a divergent lens is m times the focal length of the lens. The linear magnification produced by the lens is (A) m (B)1/m(C) m + 1 (D)1/m+ 1

The distance between an object and a divergent lens is m times the focal length of the lens. The linear magnification produced
by the lens is
(A) m (B)1/m(C) m + 1 (D)1/m+ 1

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2 Answers

Saurabh Koranglekar
askIITians Faculty 10335 Points
3 years ago
576-1666_1.PNG
Vikas TU
14149 Points
3 years ago
the magnification will be M=1 /(x+1)or in words: the magnification is the inverse of the distance of the object to it's focal point.(for a divergent lense in virtual space) in unit of focal lengths. If x is the distance to the surface, you have to add another one focal length to get the distance to the object related focal point.(substaract one convergent lenses and x usually being an absolute value.) then the inverse of that x+1 is the magnification.
 

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