The displacement of particle performing simple harmonic motion is given by, x = 8 sin wt + 6 cos wt, where distance is in cm and time is in second. The amplitude of motion is
(a) 10 cm (b) 14 cm
(c) 2 cm (d) 3.5 cm

Question

Vikas TU · Answer

Dear student Assume 6 as DC shift . Total amplitude = 8+ 6 = 14 cm Good Luck …..............................................................

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The displacement of particle performing simple harmonic motion is given by, x = 8 sin wt + 6 cos wt, where distance is in cm and time is in second. The amplitude of motion is (a) 10 cm (b) 14 cm (c) 2 cm (d) 3.5 cm

The displacement of particle performing simple harmonic motion is given by, x = 8 sin wt + 6 cos wt, where distance is in cm and time is in second. The amplitude of motion is
(a) 10 cm (b) 14 cm
(c) 2 cm (d) 3.5 cm

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The displacement of particle performing simple harmonic motion is given by, x = 8 sin wt + 6 cos wt, where distance is in cm and time is in second. The amplitude of motion is (a) 10 cm (b) 14 cm (c) 2 cm (d) 3.5 cm

The displacement of particle performing simple harmonic motion is given by, x = 8 sin wt + 6 cos wt, where distance is in cm and time is in second. The amplitude of motion is (a) 10 cm (b) 14 cm (c) 2 cm (d) 3.5 cm

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The displacement of particle performing simple harmonic motion is given by, x = 8 sin wt + 6 cos wt, where distance is in cm and time is in second. The amplitude of motion is
(a) 10 cm (b) 14 cm
(c) 2 cm (d) 3.5 cm