The displacement of an object attached to a spring and executing simple harmonic motion is given by x = 2 × 10–2 cos pt metre.The time at which the maximum speed first occurs is ?

Question

Arun · Answer

Given, displacement x = 2 × 1 0 − 2 cos π t The magnitude of velocity , v = ∣ d t d x ​ ∣ = 2 π × 1 0 − 2 sin π t So, the velocity will be maximum when sin π t = 1 where π t = 2 π ​ , 2 3 π ​ , . . So for first maximum, π t = 2 π ​ or t =

Vikas TU · Answer

x=Acosωt; dt/dx ​ =−Aωsinωt dt/dx is maximum when ωt= π/2 here ω=π ∴t= π/2π ​ = 0.5 sec............................................

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The displacement of an object attached to a spring and executing simple harmonic motion is given by x = 2 × 10–2 cos pt metre.The time at which the maximum speed first occurs is ?

The displacement of an object attached to a spring and executing simple harmonic motion is given by x = 2 × 10–2 cos pt metre.The time at which the maximum speed first occurs is ?

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The displacement of an object attached to a spring and executing simple harmonic motion is given by x = 2 × 10–2 cos pt metre.The time at which the maximum speed first occurs is ?

The displacement of an object attached to a spring and executing simple harmonic motion is given by x = 2 × 10–2 cos pt metre.The time at which the maximum speed first occurs is ?

2 Answers

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