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The compressibility of water is 4 × 10-5 per unit atmospheric pressure. 100cc of water is subjected to a change of pressure of 100 atmospheres. The change in the volume will be (a) 4 × 10-5 cc (b) 4 × 10-2 cc (c) 4 × 10-4 cc (d) 4 × 10-1 cc

Abhishek , 12 Years ago
Grade 12
anser 2 Answers
Saurabh Koranglekar

We are given the compressibility of water as 4 × 10⁻⁵ per unit atmospheric pressure, which means the fractional decrease in volume per unit increase in pressure is 4 × 10⁻⁵.

Given Data:
Initial volume of water, V = 100 cc
Change in pressure, ΔP = 100 atm
Compressibility, k = 4 × 10⁻⁵ per atm
Formula Used:
The volume change due to pressure is given by the relation:

ΔV = k × V × ΔP

where:

ΔV is the change in volume,
k is the compressibility,
V is the initial volume,
ΔP is the change in pressure.
Substituting the values:
ΔV = (4 × 10⁻⁵) × (100) × (100)

ΔV = 4 × 10⁻⁵ × 10⁴

ΔV = 4 × 10⁻¹ cc

Final Answer:
The change in volume is 0.4 cc, which corresponds to option (d) 4 × 10⁻¹ cc.


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Vikas TU
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