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The bond dissociation energy of B – F in BF3 is 646 kJ mol–1 whereas that of C – F in CF4 is 515 kj mol–1. The correct reason for higher B-F bond dissociation energy as compared to that of C-F is : (1) Smaller size of B-atom as compared to that of C-atom (2) Stronger s bond between B and F in BF3 as compared to that between C and F in CF4 (3) Significant -pp pp interaction between B and F in BF3 whereas there is no possibility of such interaction between C and F in CF4 (4) Lower degree of -p p pp interaction between B and F in BF3 than that between C and F in CF4 ?

The bond dissociation energy of B – F in BF3 is 646 kJ mol–1 whereas that of C – F in CF4 is 515 kj mol–1. The correct reason for higher B-F bond dissociation energy as compared to that of C-F is : (1) Smaller size of B-atom as compared to that of C-atom (2) Stronger s bond between B and F in BF3 as compared to that between C and F in CF4 (3) Significant -pp pp interaction between B and F in BF3 whereas there is no possibility of such interaction between C and F in CF4 (4) Lower degree of -p p pp interaction between B and F in BF3 than that between C and F in CF4 ?

Grade:12

2 Answers

Saurabh Koranglekar
askIITians Faculty 10341 Points
2 years ago
Dear student

The answer is option c

Regards
Vikas TU
14149 Points
2 years ago
The bond dissociation energy of B-F in BF3 is 646 kJ mol -1 whereas that of C-F in CF4 is 515 kJ mol -1 The correct reason for higher B-F bond dissociation energy as compared to that of C-F is Bond length between two atoms. the atomic size of boron is smaller than carbon, so the strength of the bond of B-F will higher than C-F.

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