The acceleration ‘a’ (in ms–2) of a body, starting from rest varies with time t (in s) following the equation a = 3t + 4The velocity of the body at time t = 2s will be(A) 10 ms–1 (B) 18 ms–1 (C) 14 ms–1 (D) 26 ms–1
aniket anand , 11 Years ago
Grade
2 Answers
Arun
Last Activity: 4 Years ago
Given =>
a = 3t + 4
We can find the velocity by integrating both sides and by putting in the limits!
So, by integration of both sides, we get, v=[3t2/2 + 4t]
As t=2, by putting in the value, we get!
v = 3(2)2/2 + 4(2) v= 6+8 v=14ms-1
Vikas TU
Last Activity: 4 Years ago
a = 3t + 4
We can find the velocity by integrating both sides and by putting in the limits!
So, by integration of both sides, we get, v=[3t2/2 + 4t]
As t=2, by putting in the value, we get!
v = 3(2)2/2 + 4(2) v= 6+8 v=14ms-1
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