Vikas TU
Last Activity: 4 Years ago
I = MK^2
↪so we get , the Radius of Gyration as ,
〽K = underoot (I / M)
↪So now here for getting the Radius of Gyration of an object across the diameter , we apply here the perpendicular Axis theorem
↪Iz = Ix + Iy
↪since , here , we get symmetry along all axis , we get as ,
↪( Ix = Iy)
↪Iz = 2 Ix
↪Ix = Iz/2
↪so now here, we apply , we get as
⭐K' = root 2 cm