Thank you for registering.

One of our academic counsellors will contact you within 1 working day.

Please check your email for login details.
MY CART (5)

Use Coupon: CART20 and get 20% off on all online Study Material

ITEM
DETAILS
MRP
DISCOUNT
FINAL PRICE
Total Price: Rs.

There are no items in this cart.
Continue Shopping

One mole of ideal gas required 207 J heat to rise the temperature by 10°K when heated at constant pressure. If the same gas is heated at constant volume to raise the temperature by the same 10°K the heat required is (R = 8/3 J/mole °K) (a) 1987 J (b) 29 J (c) 215.3 J (d) 124 J

One mole of ideal gas required 207 J heat to rise the temperature by 10°K when heated at constant pressure. If the same gas is heated at constant volume to raise the temperature by the same 10°K the heat required is (R = 8/3 J/mole °K)
(a) 1987 J
(b) 29 J
(c) 215.3 J
(d) 124 J

Grade:Upto college level

3 Answers

Naveen Kumar
askIITians Faculty 60 Points
7 years ago
for 1 mole,
Cp-Cv=R
heat at constant pessure,Q=1*Cp*dT
.. 207=Cp*10
Cp=20.7
heat at constant pressure,
Q’=1*Cv*dT=(Cp-R)*10=(20.7-18.3)*10J=124J
Hence answer is (D)
Siddharth Sharma
11 Points
3 years ago
for 1 mole,Cp-Cv=Rheat at constant pessure,Q=1*Cp*dT. 207=Cp*10Cp=20.7heat at constant pressure,Q’=1*Cv*dT=(Cp-R)*10=(20.7-8.314)*10J=124JHence answer is (D)
Rishi Sharma
askIITians Faculty 646 Points
one year ago
Dear Student,
Please find below the solution to your problem.

for 1 mole,
Cp-Cv=R heat at constant pessure,
Q=1*Cp*dT
207=Cp*10 Cp
=20.7
heat at constant pressure,
Q’=1*Cv*dT
=(Cp-R)*10
=(20.7-18.3)*10J
=124J
Thanks and Regards

Think You Can Provide A Better Answer ?

Provide a better Answer & Earn Cool Goodies See our forum point policy

ASK QUESTION

Get your questions answered by the expert for free