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One mole of diatomic gas is heated at 1atm from 0 k to 100 k .if the gas constant R=8.32joule/mole K,change in internal energy is approximately
Internal energy = f/2 × nR∆Tfor di atomic gas f= 5given. n =1 and ∆T = 100-0 = 100so f = 5 gh/2 ×1× 25/3 × 100= 2083.3J
HELLO THERE! There’s a formula: Where is Specific heat at constant volume, and for diatomic gas, it is Change in temperature = 100 – 0 = 100KNumber of moles (n) = 1 So, we have: THANKS!
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