M is the midpoint of side AB of equilateral triangle ABC. P is the point on BC such that AP+PM is minimum. If AB=20, then AP+PM is (a) 10 root 7 (b) 10 root 3 (c) 10 root 5 (d) 10

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Vikas TU · Answer

AP+PM = AP + PM' = AM' If APM' is a straight line equal to AM' Cos120 = (AC^2 + CM'^2 - AM'^2)/2AC*CM' AM' = 10sqrt(7)

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M is the midpoint of side AB of equilateral triangle ABC. P is the point on BC such that AP+PM is minimum. If AB=20, then AP+PM is (a) 10 root 7 (b) 10 root 3 (c) 10 root 5 (d) 10

M is the midpoint of side AB of equilateral triangle ABC. P is the point on BC such that AP+PM is minimum. If AB=20, then AP+PM is (a) 10 root 7 (b) 10 root 3 (c) 10 root 5 (d) 10

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M is the midpoint of side AB of equilateral triangle ABC. P is the point on BC such that AP+PM is minimum. If AB=20, then AP+PM is (a) 10 root 7 (b) 10 root 3 (c) 10 root 5 (d) 10

M is the midpoint of side AB of equilateral triangle ABC. P is the point on BC such that AP+PM is minimum. If AB=20, then AP+PM is (a) 10 root 7 (b) 10 root 3 (c) 10 root 5 (d) 10

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