Let r R Q Pr 4 () p = be the charge density distribution for a solid sphere of radius R and total charge Q. For a point ‘p’ inside the sphere at distance r1 from the centre of the sphere, the magnitude of electric field is –

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Arun · Answer

Dear Jayant Please check and repost the question. You can also attach an image. I will be happy to help you.

Vikas TU · Answer

If the sphere is a conducting sphere, then the electric field inside will be Zero.

If the sphere is non conducting, then consider a gaussian surface to find the electric field at a point inside.

So, according to Gauss's Law,
E{4πr^2}=1/ε∫ρdv
⇒E=14πε0^2{∫Q/rπR^4[4πr^2dr]}
⇒E=4Q/4πε0R^4r^2{∫r^3dr}
⇒E=Q/πε0R^4r^2r^4/4
⇒E=Qr^2/4πε0R^4

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Let r R Q Pr 4 () p = be the charge density distribution for a solid sphere of radius R and total charge Q. For a point ‘p’ inside the sphere at distance r1 from the centre of the sphere, the magnitude of electric field is –

Let r R Q Pr 4 () p = be the charge density distribution for a solid sphere of radius R and total charge Q. For a point ‘p’ inside the sphere at distance r1 from the centre of the sphere, the magnitude of electric field is –

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Let r R Q Pr 4 () p = be the charge density distribution for a solid sphere of radius R and total charge Q. For a point ‘p’ inside the sphere at distance r1 from the centre of the sphere, the magnitude of electric field is –

Let r R Q Pr 4 () p = be the charge density distribution for a solid sphere of radius R and total charge Q. For a point ‘p’ inside the sphere at distance r1 from the centre of the sphere, the magnitude of electric field is –

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