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LET 0>A>45 if 420(tanA+cotA)=84 Then find the value of(116cosA-58sinA)
if your question is 420(tanA+cotA)=841then420/sinAcosA=841840/sin2A=841sin2A=840/841cos2A=sqrt of (1-sin^22A)=41//841cosA=21/29sinA=20/29hence 116cosA-58sinA=116(21/29)-58(20/29)=44Thanks & RegardsRinkoo GuptaAskIITians Faculty
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