Saurabh Koranglekar
Last Activity: 5 Years ago
The O.S. ofFein Brown ring is +1. The complex formed is[Fe(H2O)5NO]SO4. The charge on anion is -2. Hence charge on the cationic complex has to be +2 as the ring is electrically neutral. The charge onFeon calculation comes out to be +2. But electron transfer take place fromNOtoFe. HenceNOandFeacquire a charge of +1 each. So the oxidation state ofNOwill be in +1 state.