Thank you for registering.

One of our academic counsellors will contact you within 1 working day.

Please check your email for login details.
MY CART (5)

Use Coupon: CART20 and get 20% off on all online Study Material

ITEM
DETAILS
MRP
DISCOUNT
FINAL PRICE
Total Price: Rs.

There are no items in this cart.
Continue Shopping

In the arrangement shown the pulley and the strings are ideal.The acceleration of block B is

In the arrangement shown the pulley and the strings are ideal.The acceleration of block B is

Question Image
Grade:11

1 Answers

Eshan
askIITians Faculty 2095 Points
3 years ago
Dear student,

The tensions are correctly shown in the figure.
Now from the contraint relationship, we can find that the acceleration of mass A is half of that of B.
Hence2a_A=a_B

From FBD of mass A,

T-mg=ma_A=m\dfrac{a_B}{2}

From FBD of mass B,

mg-\dfrac{T}{2}=ma_B
\implies a_B=\dfrac{2}{5}g

Think You Can Provide A Better Answer ?

Provide a better Answer & Earn Cool Goodies See our forum point policy

ASK QUESTION

Get your questions answered by the expert for free