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Grade: 11

                        

In the arrangement shown the pulley and the strings are ideal.The acceleration of block B is

2 years ago

Answers : (1)

Eshan
askIITians Faculty
2095 Points
							Dear student,

The tensions are correctly shown in the figure.
Now from the contraint relationship, we can find that the acceleration of mass A is half of that of B.
Hence2a_A=a_B

From FBD of mass A,

T-mg=ma_A=m\dfrac{a_B}{2}

From FBD of mass B,

mg-\dfrac{T}{2}=ma_B
\implies a_B=\dfrac{2}{5}g
2 years ago
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