In Meld’s experiment, the string vibrates in 4 loops when a 50 gram weight is placed in the pan of weight 15 gram. The make the string to vibrate is 6 loops the weight that has to be removed from the pan is(a) 0.007 kg wt(b) 0.0021 kg wt(c) 0.0036 kg wt(d) 0.0029 kg wt
sumit kumar , 10 Years ago
Grade Upto college level
2 Answers
Arun
Last Activity: 4 Years ago
p1 = 4 p2 = 2 M0 = 1 g T1 = (M0 + M1 )g = 1960 dyne T2 = (M0 + M2 )g Formula to be used : T1 p1 ² = T2 p2 ² T2=T1p1²/p2² =(M0+M1)g 4²/2² =16(Mo+m1)g/4 =1960x16/4 T2=4x1960 But as we know that (M0+M2)g=T2 (M0+M2)g=4x1960 (1+M2)980=4x1960 M2+1=4x2 M2+1=8 M2=8-1 M2=7 g wt ∴ The weight added to pan is 7 gwt