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If the cathode is a Hg electrode,the maximum weight (g) of amalgam formed from this solution ia a)446 b)200 c)400 d)225

If the cathode is a Hg electrode,the maximum weight (g) of amalgam formed from this solution ia
a)446
b)200
c)400
d)225

Grade:

1 Answers

Avinash
askIITians Faculty 1241 Points
8 years ago
When Hg is used as cathode, Na+will be reduced to Na instead of H2O. Thus formed Na will form sodium amalgam, Na-Hg.

At cathode:Na++ 1e-+ Hg -------> Na-Hg

2.0 moles of NaCl present in the solution contain 2 moles of Na+. Hence two moles of Na-Hg is formed.

The mass of 2 moles of Na-Hg = 2 (23 + 200) = 446 g.

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