If P and Q are the points of intersection of the circles x2 + y2 + 3x + 7y +2p – 5= 0 and x2 + y2 +2x + 2y – p2 = 0, then there is a circle passing through P, Q, and (1, 1) for

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Vikas TU · Answer

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If P and Q are the points of intersection of the circles x2 + y2 + 3x + 7y +2p – 5= 0 and x2 + y2 +2x + 2y – p2 = 0, then there is a circle passing through P, Q, and (1, 1) for

If P and Q are the points of intersection of the circles x2 + y2 + 3x + 7y +2p – 5= 0 and x2 + y2 +2x + 2y – p2 = 0, then there is a circle passing through P, Q, and (1, 1) for

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If P and Q are the points of intersection of the circles x2 + y2 + 3x + 7y +2p – 5= 0 and x2 + y2 +2x + 2y – p2 = 0, then there is a circle passing through P, Q, and (1, 1) for

If P and Q are the points of intersection of the circles x2 + y2 + 3x + 7y +2p – 5= 0 and x2 + y2 +2x + 2y – p2 = 0, then there is a circle passing through P, Q, and (1, 1) for

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