Thank you for registering.

One of our academic counsellors will contact you within 1 working day.

Please check your email for login details.
MY CART (5)

Use Coupon: CART20 and get 20% off on all online Study Material

ITEM
DETAILS
MRP
DISCOUNT
FINAL PRICE
Total Price: Rs.

There are no items in this cart.
Continue Shopping

If one end of a diameter of the circle 3x2 + 3y2 – 9x + 6y + 5 = 0 is (1, 2) then the other end is (A) (2, 1) (B) (2, 4) (C) (2, –4) (D) (–4, 2)

If one end of a diameter of the circle 3x2 + 3y2 – 9x + 6y + 5 = 0 is (1, 2) then the other end is
(A) (2, 1) (B) (2, 4) (C) (2, –4) (D) (–4, 2)

Grade:

2 Answers

Saurabh Koranglekar
askIITians Faculty 10341 Points
11 months ago
Dear student

The other end should be on circle and at 2R distance from the given point

Approach 2

center can be known let that for this purpose be a,b

and let other point be x,y

x+1 = 2a
y+2 = 2b

The approach you choose is upto you

Regards
Vikas TU
14149 Points
11 months ago
Dear student 
You can also use hit and trail method , 
Just put the points in the equation  of circle.
Good Luck 
Cheers …................................

Think You Can Provide A Better Answer ?

Provide a better Answer & Earn Cool Goodies See our forum point policy

ASK QUESTION

Get your questions answered by the expert for free