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If one end of a diameter of the circle 3x2 + 3y2 – 9x + 6y + 5 = 0 is (1, 2) then the other end is (A) (2, 1) (B) (2, 4) (C) (2, –4) (D) (–4, 2)

If one end of a diameter of the circle 3x2 + 3y2 – 9x + 6y + 5 = 0 is (1, 2) then the other end is
(A) (2, 1) (B) (2, 4) (C) (2, –4) (D) (–4, 2)

Grade:

2 Answers

Saurabh Koranglekar
askIITians Faculty 10336 Points
2 years ago
Dear student

The other end should be on circle and at 2R distance from the given point

Approach 2

center can be known let that for this purpose be a,b

and let other point be x,y

x+1 = 2a
y+2 = 2b

The approach you choose is upto you

Regards
Vikas TU
14149 Points
2 years ago
Dear student 
You can also use hit and trail method , 
Just put the points in the equation  of circle.
Good Luck 
Cheers …................................

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