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Given the standard electrode potentials, K+/K = -2.93V, Ag+/Ag = 0.80V, Hg2+/Hg = 0.79V, Mg2+/Mg = -2.37 V, Cr3+/Cr = - 0.74V Arrange these metals in their increasing order of reducing power.?

vicky , 12 Years ago
Grade Upto college level
anser 1 Answers
Naveen Kumar
Here lower the value of reduction potential(with sign), more is the reducing power of metal. Hence, in all of these given, pottasium is of the most reducing character and Ag is the lowest reducing agent.
Now we can easily arrange these, according to the values.
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Last Activity: 11 Years ago
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