Given P(x) = x4 +ax3 + bx2 +cx + d such that x = 0 is the only real root of P' (x) =0. If P(–1)

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Given P(x) = x4 +ax3 + bx2 +cx + d such that x = 0 is the only real root of P' (x) =0. If P(–1) < P(1), then in the interval [–1,1] -

Saurabh Koranglekar · Answer

Vikas TU · Answer

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Given P(x) = x4 +ax3 + bx2 +cx + d such that x = 0 is the only real root of P' (x) =0. If P(–1) < P(1), then in the interval [–1,1] -

Given P(x) = x4 +ax3 + bx2 +cx + d such that x = 0 is the only real root of P' (x) =0. If P(–1) < P(1), then in the interval [–1,1] -

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Given P(x) = x4 +ax3 + bx2 +cx + d such that x = 0 is the only real root of P' (x) =0. If P(–1) < P(1), then in the interval [–1,1] -

Given P(x) = x4 +ax3 + bx2 +cx + d such that x = 0 is the only real root of P' (x) =0. If P(–1) < P(1), then in the interval [–1,1] -

2 Answers

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