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Estimate the wavelength at which plasma reflection will occur for a metal having the density of electrons N ˜ 4 × 10 (27) m/3. Taking e0 = 10 (-11) and m ˜ 10 (-30) , where these quantities are in proper SI units.

Jayant Kumar , 12 Years ago
Grade 11
anser 2 Answers
Saurabh Koranglekar

Estimation of Plasma Reflection Wavelength

We are given:

  • Electron number density, \( N \approx 4 \times 10^{27} \, \text{m}^{-3} \)
  • Permittivity of free space, \( \varepsilon_0 = 10^{-11} \, \text{F/m} \)
  • Electron mass, \( m = 10^{-30} \, \text{kg} \)
  • Elementary charge, \( e = 1.6 \times 10^{-19} \, \text{C} \)

1. Formula for Plasma Frequency

\( \omega_p = \sqrt{\frac{N e^2}{\varepsilon_0 m}} \)

2. Substitute the Values

\( \omega_p = \sqrt{ \frac{(4 \times 10^{27}) \times (1.6 \times 10^{-19})^2 }{ (10^{-11}) \times (10^{-30}) } } \)

Calculate step-by-step:

  • \( e^2 = (1.6 \times 10^{-19})^2 = 2.56 \times 10^{-38} \)
  • Numerator: \( 4 \times 10^{27} \times 2.56 \times 10^{-38} = 1.024 \times 10^{-10} \)
  • Denominator: \( 10^{-11} \times 10^{-30} = 10^{-41} \)
  • So, \( \omega_p = \sqrt{ \frac{1.024 \times 10^{-10} }{10^{-41}} } = \sqrt{1.024 \times 10^{31}} \)
  • \( \omega_p \approx 1.012 \times 10^{15} \, \text{rad/s} \)

3. Convert to Wavelength

\( \lambda_p = \frac{2\pi c}{\omega_p} \), where \( c = 3 \times 10^8 \, \text{m/s} \)
  • \( \lambda_p = \frac{2 \pi \times 3 \times 10^8}{1.012 \times 10^{15}} \)
  • \( \lambda_p \approx \frac{1.884 \times 10^9}{1.012 \times 10^{15}} \approx 1.86 \times 10^{-6} \, \text{m} \)
🔍 The estimated wavelength for plasma reflection is:
\( \lambda_p \approx 1.86 \, \mu\text{m} \) (micrometers)
Last Activity: 6 Years ago
Vikas TU
576-2379_z.PNG
Dear student 
Please refer the clear image , 
The image above does not looks good , it is blurr.
Hope for the best 
Good Luck 
Cheers 
Last Activity: 6 Years ago
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