Both the roots of the equation (x - b)(x - c) + (x - a)(x - c) + (x - a)(x - b) = 0 are always
A. positive B. negative C. real D. imaginary

Question

Both the roots of the equation (x - b)(x - c) + (x - a)(x - c) + (x - a)(x - b) = 0 are always A. positive B. negative C. real D. imaginary

Saurabh Koranglekar · Answer

Dear student The answer is option c Regards

Vikas TU · Answer

Dear student D≥0 Hence, both roots are always real . …....................................................................................................

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Both the roots of the equation (x - b)(x - c) + (x - a)(x - c) + (x - a)(x - b) = 0 are always A. positive B. negative C. real D. imaginary

Both the roots of the equation (x - b)(x - c) + (x - a)(x - c) + (x - a)(x - b) = 0 are always
A. positive B. negative C. real D. imaginary

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Both the roots of the equation (x - b)(x - c) + (x - a)(x - c) + (x - a)(x - b) = 0 are always A. positive B. negative C. real D. imaginary

Both the roots of the equation (x - b)(x - c) + (x - a)(x - c) + (x - a)(x - b) = 0 are always A. positive B. negative C. real D. imaginary

2 Answers

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Both the roots of the equation (x - b)(x - c) + (x - a)(x - c) + (x - a)(x - b) = 0 are always
A. positive B. negative C. real D. imaginary