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An ion with mass number 37 possesses one unit of negative charge. If the ion conatins 11.1% more neutrons than the electrons, find the symbol of the ion.

An ion with mass number 37 possesses one unit of negative charge. If the ion conatins 11.1% more neutrons than the electrons, find the symbol of the ion.

Grade:12

1 Answers

Gaurav
askIITians Faculty 164 Points
7 years ago
Hello Student
Let the number of electrons in the ion carrying a negative charge be x.
Then, as per the question, the number of neutrons present = x + 11.1% of x
= x + 0.111 x
= 1.111 x

Since, the ion contains one negative charge, the number of electrons in the neutral atom = (x – 1)
So, the number of protons in the neutral atom = x – 1

Again as per the question,
Mass number of the ion = 37
So, (x – 1) + 1.111x = 37
2.111x = 38
x = 18

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