Vikas TU
Last Activity: 4 Years ago
Concentration is given in percent so that take mass of the solution = 100 g
Mass of non-volatile solute = 2% = 2g mass of the solvent = (100 — 2) = 98 g
Molecular mass of solvent (water) = 18
We have to find molecular mass of solute,
The vapour pressure of pure boiling water = 1atm = 1.013 bar.
Change in vapour pressure = (1.013 — 1.004)
= 0.009 bar
° - / ° = w2 × m1 / w1 × m2
0.009 / 1.013 bar = 2g / m2 × 18 g
m2 = 41.35 g
Hence,
Molar mass of the solute is 41.35 g
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