Vikas TU
Last Activity: 5 Years ago
By stretch the wire till its length is triple while the volume remains constant, the cross sectional area is three times less compared to its original value.
Therefore, when you computed the ratio between the original and the new value of the resistance, it would be:
R/R' = (L/A) / (L'/A') = 1/9
Thus, the new resistance would be R' = 9R = 45O