Saurabh Koranglekar
Last Activity: 4 Years ago
Since the ball rebounds with same speed but in opposite direction.
So, change in linear momentum of one ballΔP=Pf−Pi=mu−(−mu)=2mu
Number of ball hitting the surface per second isn
So, total change in momentum in one secondΔPT=n×2mu
So, force acting on the surfaceF=2mnu