A wall is hit elastically and normally by n balls per second, all the balls have the same mass m and are moving with the same velocity u. the force exerted by the balls on the wall is___________

Question

Saurabh Koranglekar · Answer

Since the ball rebounds with same speed but in opposite direction.
So, change in linear momentum of one ballΔP=Pf−Pi=mu−(−mu)=2mu
Number of ball hitting the surface per second isn
So, total change in momentum in one secondΔPT=n×2mu
So, force acting on the surfaceF=2mnu

Vikas TU · Answer

When a ball hits normally on surface elastically then it rebounds with same velocity. F = m * dv/dt F = nM * (u - (-u)) / t F = 2nM / t Given that n/t = N ∴ F = 2NMu

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A wall is hit elastically and normally by n balls per second, all the balls have the same mass m and are moving with the same velocity u. the force exerted by the balls on the wall is___________

A wall is hit elastically and normally by n balls per second, all the balls have the same mass m and are moving with the same velocity u. the force exerted by the balls on the wall is___________

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A wall is hit elastically and normally by n balls per second, all the balls have the same mass m and are moving with the same velocity u. the force exerted by the balls on the wall is___________

A wall is hit elastically and normally by n balls per second, all the balls have the same mass m and are moving with the same velocity u. the force exerted by the balls on the wall is___________

2 Answers

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