A vessel at 1000 K contains CO2 with a pressure of 0.5 atm. Some of the CO2 is converted into CO on the addition of graphite. If the total pressure at equilibrium is 0.8 atm, the value of K is ?
A 0.18 atm
B 1.8 atm
C 3 atm
D 0.3 atm
Jayant Kumar , 11 Years ago
Grade 11
2 Answers
Saurabh Koranglekar
Last Activity: 4 Years ago
Dear student
The answer is option b
Regards
Vikas TU
Last Activity: 4 Years ago
initially 0.5 0 0
at eq'm 0.5-x 0 2x
As solids do not contribute to pressure.
Given total pressure= 0.5-x+2x=0.8
x=0.3
Thus pco2 = 0.5-0.3 = 0.2
pco = 2*0.3
So eq'm constant will be: kp = p(co)^2 / (pco2) = 1.8
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