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A train is moving along a straight line with a constant acceleration ‘a’. A boy standing in the train throws a ball forward with a speed of 10 m/s, at an angle of 60 ° to the horizontal. The boy has to move forward by 1.15 m inside the train to catch the ball back at the initial height. The acceleration of the train, in m/s 2, is ?

A train is moving along a straight line with a constant acceleration ‘a’. A boy standing in the train throws a ball forward with a speed of 10 m/s, at an angle of 60 ° to the horizontal. The boy has to move forward by 1.15 m inside the train to catch the ball back at the initial height. The acceleration of the train, in m/s 2, is ?

Grade:11

2 Answers

Arun
25750 Points
3 years ago
Ball performs parabolic motion,
For vertical motion,
s=ut−21​gt2
∴0=10sin60ot−21​×10×t2
∴t=3​s
For horizontal motion,
s=ut+21​at2
∴1.15=10cos60o×3​−21​a(3)
∴a=5m/s2
Vikas TU
14149 Points
3 years ago
uy=10sin 60=53√m/s
⇒     t=2uyg=2×53√10=3√s
Sx=uxt+12axt2
1.15=5×t−12a×t2
1.15=5×3√−32a
 3a2=5×1.73−1.15=8.65−1.15
 3a2=7.5  
 ⇒   a=153=5m/s2
 

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